数学分析提高随机推荐周民强教材习题第 2 章 反常积分2.1 函数在无穷区间上的积分定积分、瑕积分与反常积分繁琐不看本题本题讨论已掌握查看解析收入错题#18523试证明下列命题:(1) I=∫0π/2dx(a2cos2x+b2sin2x)2=π(a2+b2)4∣a3b3∣(a,b>0)I = {\int }_{0}^{\pi /2}\frac{\mathrm{d}x}{{\left( {a}^{2}{\cos }^{2}x + {b}^{2}{\sin }^{2}x\right) }^{2}} = \frac{\pi \left( {{a}^{2} + {b}^{2}}\right) }{4\left| {{a}^{3}{b}^{3}}\right| }\left( {a,b > 0}\right)I=∫0π/2(a2cos2x+b2sin2x)2dx=4∣a3b3∣π(a2+b2)(a,b>0) .(2) 设 f(x)=∫0xcos(1t)dtf\left( x\right) = {\int }_{0}^{x}\cos \left( \frac{1}{t}\right) \mathrm{d}tf(x)=∫0xcos(t1)dt ,则 f′(0)=0{f}^{\prime }\left( 0\right) = 0f′(0)=0 .