线性代数基础矩阵运算线性代数做题本(一)解答版解答题查看解析已掌握收入错题本题讨论不看本题#8443设 A=(010100001),B=(100001010),C=(1−4320−11−20)A = \left(\begin{array}{lll} 0 & 1 & 0 \\ 1 & 0 & 0 \\ 0 & 0 & 1 \end{array}\right),B = \left(\begin{array}{lll} 1 & 0 & 0 \\ 0 & 0 & 1 \\ 0 & 1 & 0 \end{array}\right),C = \left(\begin{array}{rrr} 1 & - 4 & 3 \\ 2 & 0 & - 1 \\ 1 & - 2 & 0 \end{array}\right)A=010100001,B=100001010,C=121−40−23−10,满足 AXB=C{AXB} = CAXB=C,求矩阵 XXX.