高等数学提高一元积分选择题查看解析已掌握收入错题本题讨论不看本题#9709limn→∞ln(1+1n)2(1+2n)2⋯(1+nn)2n=\mathop{\lim }\limits_{n \rightarrow \infty }\ln \sqrt[n]{{\left(1 + \frac{1}{n}\right) }^{2}{\left(1 + \frac{2}{n}\right) }^{2}\cdots {\left(1 + \frac{n}{n}\right) }^{2}} =n→∞limlnn(1+n1)2(1+n2)2⋯(1+nn)2=‾\underline{\qquad}A. ∫12ln2x dx{\int }_{1}^{2}{\ln }^{2}x\,\mathrm{d}x∫12ln2xdx.B. 2∫12lnx dx2{\int }_{1}^{2}\ln x\,\mathrm{d}x2∫12lnxdx.C. 2∫12ln(1+x)dx2{\int }_{1}^{2}\ln \left({1 + x}\right) \mathrm{d}x2∫12ln(1+x)dx.D. ∫12ln2(1+x)dx{\int }_{1}^{2}{\ln }^{2}\left({1 + x}\right) \mathrm{d}x∫12ln2(1+x)dx.
